560=x^2+(X+8)

Solution for 560=x^2+(X+8) equation:

560=x^2+(x+8)

We move all terms to the left:

560-(x^2+(x+8))=0


We calculate terms in parentheses: -(x^2+(x+8)), so:

x^2+(x+8)

We get rid of parentheses

x^2+x+8

Back to the equation:

-(x^2+x+8)


We get rid of parentheses

-x^2-x-8+560=0

We add all the numbers together, and all the variables

-1x^2-1x+552=0

a = -1; b = -1; c = +552;
Δ = b2-4ac
Δ = -12-4·(-1)·552
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-47}{2*-1}=\frac{-46}{-2}
=+23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+47}{2*-1}=\frac{48}{-2}
=-24
$